20x^2-17x=3

Solution for 20x^2-17x=3 equation:

20x^2-17x=3

We move all terms to the left:

20x^2-17x-(3)=0

a = 20; b = -17; c = -3;
Δ = b2-4ac
Δ = -172-4·20·(-3)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-23}{2*20}=\frac{-6}{40}
=-3/20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+23}{2*20}=\frac{40}{40}
=1
$